Sort First-digit of Integer Number

Maybe some of you know how to get first digit of number. For example this question: "how to get '2' from this number "2378940048"? Literally in logic, we can do this question by dividing this number with 10 and it will remain 237894004.8 (in decimal) and  we will get 237894004 (in integer), without 8 because integer does not recognize fraction /floating value. It's easy, isn't it?. Then, here it is!

• Using Method First-digit

package firstletter;
import java.util.*;
public class FirstLetter {

    public static void main(String[] args) {
        int a; //declare the variable
        
        Scanner input = new Scanner(System.in);
        
        //Input from the user
        System.out.print("Please enter your number: ");
        a = input.nextInt();
        
        System.out.println("So the first digit of this '" +a+"' is: "+firstDigit(a));
    }//end main method
    
    public static int firstDigit(int n)
    {
        //Condition to determine the value 
       while (n < -9 || 9 < n) 
           n /= 10;
       return Math.abs(n); //Math absolute is used to round the value
    }//end First digit method
}

• Using Single Method in main

package firstletter;
import java.util.*;
public class FirstLetter {

    public static void main(String[] args) {
        int a; //declare the variable
        
        Scanner input = new Scanner(System.in);
        
        //Input from the user
        System.out.print("Please enter your number: ");
        a = input.nextInt();
        
//Condition to determine the value 
       while (a < -9 || 9 < a ) {
           a /= 10;
}
        System.out.println("So the first digit of this '" +a +"' is: "+a);
   
}//end main method